n版四年級英語下冊

題目給我，我告訴你

3. wants to know to draw
4. do
5. go shopping does shopping
6. making play
7. Watching is
8. hopes to be
9. Does listen
10. does do

首先困頃(1+1/磨扮x)^(x+1)>e（單調(diào)減極限是e）即e*x^(x+1)<(x+1)^(x+1)
下用數(shù)學(xué)歸納法證明
如果命題對n成立（原式等價(jià)于1^n+2^n+…+n^n則1^(n+1)+2^(n+1)+…瞎尺灶+n^(n+1)+(n+1)^(n+1)
<=n*(1^n+2^n+…+n^n)+(n+1)^(n+1)
<=n*e/(e-1)*n^n+(n+1)^(n+1)
<=e/(e-1)*n^(n+1)+(n+1)^(n+1)
<=1/(e-1)*(n+1)^(n+1)+(n+1)^(n+1)
=e/(e-1)*(n+1)^(n+1)

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x∧n-x∧n-2
=x∧n-x∧n÷4
=(1-1/4)x∧n
=3/4x∧n。

就是N項(xiàng)之后滿足條件就行.這體現(xiàn)了極限的本質(zhì),反映了后面無窮多項(xiàng),不管前有限項(xiàng)是什么.