求各位數(shù)學(xué)大神看一下這道題怎么解

x(x+1)(x+2)(x+3)
=x(x+3)×(x+1)(x+2)
=x(x+3)[x(x+3)+2]
=[x(x+3)]2+2x(x+3)
=[(√5-3)/2×(√5+3)/2]2+
2(√5-3)/2×(√5+3)/2
=(-1)2+2×(-1)
=-1

x=(√5 -3)/2
x+3 =(√5 +3)/2
x(x+3) = (5-9)/4 = -1
x+1 =(√5 -1)/2
x+2 =(√5 +1)/2
(x+1)(x+2) = (5-1)/4 =1
x(x+1)(x+2)(x+3) = (-1)(1) =-1

解：∵X=（√5-3）/2
∴X+1=（√5-3）/2+2/2=（√5-1）/2
X+2=（√5-3）/2+4/2=（√5+1）/2
X+3=（√5-3）/2+6/2=（√5+3）/2
∴X（X+1）（X+2）（X+3）
=（√5-3）/2×（√5+3）/2×（√5-1）/2×（√5+1））/2
=（5-9）/4×（5-1）/4
=-4/4×4/4
=-1